aboutsummaryrefslogtreecommitdiff
diff options
context:
space:
mode:
authorhinder <hinder@57fe0bb3-ccba-405f-9b23-de0201f165b7>2011-10-25 12:34:07 +0000
committerhinder <hinder@57fe0bb3-ccba-405f-9b23-de0201f165b7>2011-10-25 12:34:07 +0000
commitb1ddd83f2e82b9c3064c3e05b44fc309369c3006 (patch)
tree7035766dcc47235f8e727905290c940d916392f6
parent922be71c197f71c57a33259a82ab38399c7cbb20 (diff)
documentation.tex: Add braces for htlatex
git-svn-id: http://svn.einsteintoolkit.org/cactus/EinsteinBase/HydroBase/trunk@44 57fe0bb3-ccba-405f-9b23-de0201f165b7
-rw-r--r--doc/documentation.tex12
1 files changed, 6 insertions, 6 deletions
diff --git a/doc/documentation.tex b/doc/documentation.tex
index ec8d709..504bd31 100644
--- a/doc/documentation.tex
+++ b/doc/documentation.tex
@@ -182,7 +182,7 @@ so that there are no misunderstandings between thorns a specific
set of units is suggested. These units are derived from the
conventions
\begin{eqnarray}
- M_\mathrm{sun} = 1 &;& c = G = 1
+ M_{\mathrm{sun}} = 1 &;& c = G = 1
\end{eqnarray}
which are commonly used in astrophysics and in relativity.
The former sets the mass scale to the solar one and the latter
@@ -198,13 +198,13 @@ We assume the following definitions and constants of nature:
\\
\epsilon_0 & = & \frac{1}{\mu_0 c^2}
\\
- M_\mathrm{sun} & = & 1.98892\cdot10^{30}\, \mathrm{kg}
+ M_{\mathrm{sun}} & = & 1.98892\cdot10^{30}\, \mathrm{kg}
\end{eqnarray}
This corresponds to the following units for mass, length, time, and
magnetic field:
\begin{eqnarray}
- [M] & = & M_\mathrm{sun}
+ [M] & = & M_{\mathrm{sun}}
\\{}
[L] & = & [M]\; G/c^2
\\{}
@@ -216,11 +216,11 @@ magnetic field:
Inserting the SI units into the above unit correspondences,
we find the following conversion factors:
\begin{eqnarray}
- [L] & = & 1\, M_\mathrm{sun} \equiv 1.477\, \mathrm{km}
+ [L] & = & 1\, M_{\mathrm{sun}} \equiv 1.477\, \mathrm{km}
\\{}
- [T] & = & 1\, M_\mathrm{sun} \equiv 4.92673\, \mathrm{\mu s}
+ [T] & = & 1\, M_{\mathrm{sun}} \equiv 4.92673\, \mathrm{\mu s}
\\{}
- [B] & = & 1\, \sqrt{\mu_0} /M_\mathrm{sun} \equiv 8.344956\cdot 10^{15}\, \mathrm{T},
+ [B] & = & 1\, \sqrt{\mu_0} /M_{\mathrm{sun}} \equiv 8.344956\cdot 10^{15}\, \mathrm{T},
\end{eqnarray}
where T (Tesla) is the magnetic field unit in SI,
$1\,\mathrm{T}=1\,\mathrm{N/(A\cdot m)}$, or in its cgs equivalent,