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authorrideout <rideout@6a38eb6e-646e-4a02-a296-d141613ad6c4>2001-12-04 14:57:33 +0000
committerrideout <rideout@6a38eb6e-646e-4a02-a296-d141613ad6c4>2001-12-04 14:57:33 +0000
commitc8e6172e3fa051d85c128d20e20c8e3df69038f0 (patch)
tree9529629c2bf617dddc9f749c7a1b731d1b7c9d3f /doc/documentation.tex
parentea1e3b891adb437b9938d801741737d117fc37d6 (diff)
Fixed some typos.
git-svn-id: http://svn.cactuscode.org/arrangements/CactusBase/Boundary/trunk@163 6a38eb6e-646e-4a02-a296-d141613ad6c4
Diffstat (limited to 'doc/documentation.tex')
-rw-r--r--doc/documentation.tex8
1 files changed, 4 insertions, 4 deletions
diff --git a/doc/documentation.tex b/doc/documentation.tex
index 997487e..25c808b 100644
--- a/doc/documentation.tex
+++ b/doc/documentation.tex
@@ -302,14 +302,14 @@ At a given boundary only the derivatives in the normal direction are
considered. Notice that $u(r-vt)$ has disappeared, but we still do
not know the value of $H$.
-To get $H$ we do is the following: The expression is evaluated one
-point in from the boundary and solved for $H$ there. Now need a way of
-extrapolating $H$ to the boundary is required. For this, assume that
+To get $H$ we do the following: The expression is evaluated one
+point in from the boundary and solved for $H$ there. Now we need a way of
+extrapolating $H$ to the boundary. For this, assume that
$H$ falls off as a power law:
\begin{equation}
H = \frac{k}{r^n} \qquad \mbox{which gives} \qquad d_i H = - n \frac{H}{r}
\end{equation}
-The value of $n$ is is defined by the parameter {\tt radpower}.
+The value of $n$ is defined by the parameter {\tt radpower}.
If this parameter is negative, $H$ is forced to be zero (this
corresponds to pure outgoing waves and is the default).