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author | rideout <rideout@6a38eb6e-646e-4a02-a296-d141613ad6c4> | 2001-12-04 14:57:33 +0000 |
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committer | rideout <rideout@6a38eb6e-646e-4a02-a296-d141613ad6c4> | 2001-12-04 14:57:33 +0000 |
commit | c8e6172e3fa051d85c128d20e20c8e3df69038f0 (patch) | |
tree | 9529629c2bf617dddc9f749c7a1b731d1b7c9d3f /doc/documentation.tex | |
parent | ea1e3b891adb437b9938d801741737d117fc37d6 (diff) |
Fixed some typos.
git-svn-id: http://svn.cactuscode.org/arrangements/CactusBase/Boundary/trunk@163 6a38eb6e-646e-4a02-a296-d141613ad6c4
Diffstat (limited to 'doc/documentation.tex')
-rw-r--r-- | doc/documentation.tex | 8 |
1 files changed, 4 insertions, 4 deletions
diff --git a/doc/documentation.tex b/doc/documentation.tex index 997487e..25c808b 100644 --- a/doc/documentation.tex +++ b/doc/documentation.tex @@ -302,14 +302,14 @@ At a given boundary only the derivatives in the normal direction are considered. Notice that $u(r-vt)$ has disappeared, but we still do not know the value of $H$. -To get $H$ we do is the following: The expression is evaluated one -point in from the boundary and solved for $H$ there. Now need a way of -extrapolating $H$ to the boundary is required. For this, assume that +To get $H$ we do the following: The expression is evaluated one +point in from the boundary and solved for $H$ there. Now we need a way of +extrapolating $H$ to the boundary. For this, assume that $H$ falls off as a power law: \begin{equation} H = \frac{k}{r^n} \qquad \mbox{which gives} \qquad d_i H = - n \frac{H}{r} \end{equation} -The value of $n$ is is defined by the parameter {\tt radpower}. +The value of $n$ is defined by the parameter {\tt radpower}. If this parameter is negative, $H$ is forced to be zero (this corresponds to pure outgoing waves and is the default). |