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authorAnton Khirnov <anton@khirnov.net>2022-04-13 09:30:52 +0200
committerAnton Khirnov <anton@khirnov.net>2023-04-09 15:47:45 +0200
commit98b41d0bd22258618fd8885368e8493e56208ccb (patch)
tree45ac3a1425aaed99b0f47cd012247238bb01dab2 /fftools/sync_queue.c
parent090950f8327c01b1775615b1da723dc6cc8a30a0 (diff)
fftools/sync_queue: document overall design
Diffstat (limited to 'fftools/sync_queue.c')
-rw-r--r--fftools/sync_queue.c35
1 files changed, 35 insertions, 0 deletions
diff --git a/fftools/sync_queue.c b/fftools/sync_queue.c
index 7c348af300..0aee4ef5ff 100644
--- a/fftools/sync_queue.c
+++ b/fftools/sync_queue.c
@@ -28,6 +28,41 @@
#include "objpool.h"
#include "sync_queue.h"
+/*
+ * How this works:
+ * --------------
+ * time: 0 1 2 3 4 5 6 7 8 9 10 11 12 13
+ * -------------------------------------------------------------------
+ * | | | | | | | | | | | | | |
+ * | ┌───┐┌────────┐┌───┐┌─────────────┐
+ * stream 0| │d=1││ d=2 ││d=1││ d=3 │
+ * | └───┘└────────┘└───┘└─────────────┘
+ * ┌───┐ ┌───────────────────────┐
+ * stream 1│d=1│ │ d=5 │
+ * └───┘ └───────────────────────┘
+ * | ┌───┐┌───┐┌───┐┌───┐
+ * stream 2| │d=1││d=1││d=1││d=1│ <- stream 2 is the head stream of the queue
+ * | └───┘└───┘└───┘└───┘
+ * ^ ^
+ * [stream 2 tail] [stream 2 head]
+ *
+ * We have N streams (N=3 in the diagram), each stream is a FIFO. The *tail* of
+ * each FIFO is the frame with smallest end time, the *head* is the frame with
+ * the largest end time. Frames submitted to the queue with sq_send() are placed
+ * after the head, frames returned to the caller with sq_receive() are taken
+ * from the tail.
+ *
+ * The head stream of the whole queue (SyncQueue.head_stream) is the limiting
+ * stream with the *smallest* head timestamp, i.e. the stream whose source lags
+ * furthest behind all other streams. It determines which frames can be output
+ * from the queue.
+ *
+ * In the diagram, the head stream is 2, because it head time is t=5, while
+ * streams 0 and 1 end at t=8 and t=9 respectively. All frames that _end_ at
+ * or before t=5 can be output, i.e. the first 3 frames from stream 0, first
+ * frame from stream 1, and all 4 frames from stream 2.
+ */
+
typedef struct SyncQueueStream {
AVFifo *fifo;
AVRational tb;